What is s_y at t = 0 in the vertical position equation s_y = -(1/2) g t^2 + v0y t + s_y0?

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Multiple Choice

What is s_y at t = 0 in the vertical position equation s_y = -(1/2) g t^2 + v0y t + s_y0?

Explanation:
The question tests what the vertical position is at the initial moment. At t = 0, the terms that depend on time vanish: -(1/2) g t^2 becomes 0 and v0y t becomes 0. What’s left is s_y0, which is the initial vertical position. So s_y(0) equals s_y0, the starting height.

The question tests what the vertical position is at the initial moment. At t = 0, the terms that depend on time vanish: -(1/2) g t^2 becomes 0 and v0y t becomes 0. What’s left is s_y0, which is the initial vertical position. So s_y(0) equals s_y0, the starting height.

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